運算練習(xí)題，已知有一數(shù)組Arr1[Num1，Num2，Num3]，求它們分別乘以另一數(shù)組Arr2[Num4,Num5]得到數(shù)組Arr3[Num6,Num7,Num8,Num9,Num10,Num11]，再求數(shù)組SumArr3的總和等于多少？求大佬使用ST結(jié)構(gòu)文本循環(huán)語句完成告知思路和標(biāo)簽定義，題目的意思相當(dāng)于：Num1*Num4+Num2*Num4+Num3*Num4+Num1*Num5+Num2*Num5+Num3*Num5 = SumArr?

假如這三個數(shù)組分別是X(0,1,2)    Y(0,1)    z(1,2,3,4,5,6)    變量初值 ii:=0;     h:=0;
IF m1 THEN
    FOR i:=1 to 6 do
        If i<=3 then
            z(i):=x(ii)*y(0);
        Elsif i>3 then
            ii:=0;
            z(i):=x(ii)*y(1);
        End_if;

        If i=6 then
           h:=z(1)+z(2)+z(3)+z(4)+z(5)+z(6);
           i:=0;
           ii:=0;
           m1:=false;
         end_if;

         ii:=ii+1;
    End_for;
Else
   ii:=0;
End_if;

Z1:=x0*y0
Z2:=x1*y0
Z3:=x2*y0
Z4:=x0*y1
Z5:=x1*y1
Z6:=x2*y1
理論上應(yīng)該可以實現(xiàn)樓主的要求，具體可能需要測試